Percent Yield Of A Precipitate Essay

1223 words - 5 pages

PurposeThe purpose of the experiment is to determine the percent yield of the precipitate; by performing double displacement reaction between solutions of two different compounds.IntroductionFirst of all when making a solution of two different compounds; there will many variables that can be considered during the experiment. However, the variables are controlled variables.Controlled Variables∙amount of water that will be dissolved with the compound (amount of water until the compound is dissolved)∙temperature inside the laboratory (constant)∙air pressure (constant)∙mass of reactant used (mass is less that 3g)When we consider a double displacement reaction; we will need to think about the solubility rules. In our experiment we consider the rule that "Most nitrate (NO3-) salts are soluble." And "Most sulfate are soluble. Notable exceptions are BaSO4......" By this rules we can check the solutions that we will use during the experiment that whether it is soluble or not. Also, we can check after the reaction, which of the compound is the precipitate. Hence, before the experiment it is possible to predict whether the reaction will include precipitate by the solubility rules. In this case the precipitate will be BaSO4.HypothesisIn this experiment the reaction equation will be:CuSO4?H2O + Ba(NO3)2 →Ba SO4+ Cu(NO3)2In Lab#6 that we have done in Dec 15 2003; we have found out that the mole for hydrate in copper (II) sulfate is 5. Thus, by this experiment I will continue to use the answer that I have found in Lab#6. So by using the knowledge from Lab#6 the reaction equation will be:CuSO45H2O + Ba(NO3)2 →BaSO4+ Cu(NO3)2We can measure the mass of copper (Ⅱ) sulfate and the mass of the barium nitrate. Thus, we can calculate the theoretical yield of barium sulfate. By this, it is possible to find out the percent yield of barium sulfate; if we found the experimental yield.The percent yield of barium sulfate= experimental yield of barium sulfatetheoretical yield of barium sulfateMaterialsfilter papercopper(Ⅱ) sulfatebarium nitrateglass stirring rodbeaker (250ml)two volumetric flasks (50ml)balanceplastic trayProcedurei. Take out the solutes of Cu(II)SO4 and Ba(NO3)2 and measure them approximately3g.ii. Insert each of the solution inside a volumetric flask and mix these solutes into water and stir it with a glass stirring rod until it dissolves.iii.After it dissolved; mix the two solutions into a beaker.iv.Make sure there is a precipitate inside the beaker.v.Before you filter the solution that is made in the beaker; measure the mass of the filter paper.vi.Now filter the solution contained inside the beaker.vii.Leave it to filter for a while.viii.After it has filtered; place it in the oven for the night.ix.After it has dried up; measure the mass of filter paper.Data tableTable1- the change of the state and the mass of Cu(II)SO4 and Ba(NO3)2State (before inserted in water)State(after inserted in water)Mass (+0.002g)Cu...

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